Raman had some money. He spent 
of it on education and 
of the remainder on food. He saved the rest.
(A) What fraction of his money was spent on food?
(B) If Raman spent ₹ 2400 on food, then how much did he save?
| (A) | (B) | |
| A | 1/25 | ₹ 2400 |
| B | 8/25 | ₹ 3600 |
| C | 8/25 | ₹ 2400 |
| D | 1/25 | ₹ 3600 |
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Ans 1:
Class : Class 9
Solution=Let the quantity of water in bottleP = 3x and that of in bottle Q = 4x.According to question,⇒ 20(3x – 40) = 4x × 13⇒ 60x – 800 = 52x ⇒ 8x = 800 ⇒ x = 100So, quantity of water in bottle P = 3 × 100= 300 mLans.-c
Ans 3:
Class : Class 7
Let the quantity of water in bottleP = 3x and that of in bottle Q = 4x.According to question,⇒ 20(3x – 40) = 4x × 13⇒ 60x – 800 = 52x ⇒ 8x = 800 ⇒ x = 100So, quantity of water in bottle P = 3 × 100= 300 mL
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Ans 1:
Class : Class 10
B cause the rule is based on multiplication 0 input will be 0 as out put cause if you multiply 0 by 0 you get 0 and other answers don't have that as an option
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