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Ans 1:
Class : Class 8
you are absoulutely wrong imagine how many computers will be needed suppose you are not able to finish the paper on time teachers give you extra time you may come across my fate last year 2nd level i had 3 ques left in achiever's section and the person snatched my paper they had only given us 45 mins and then when i saw the result i got 34 out of 40 i may have come world no. 1 very bad school management
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Ans 2:
Class : Class 10
I find this question too high for Class 1. Anyway, I'll answer this.
Given that a+b=27; b-a=9; a+b+c+d=36. Substituting a+b=27 in a+b+c+d=36, 27+c+d=36-27=9. c+d=9; d-c=3.
Adding a+b and b-a, a+b+b-a=27+9, 2b=36, b=18. Therefore a=27-18=9.
Adding c+d and d-c, c+d+d-c=9+3, 2d=12, d=6. Therefore c=6-3=3.
Now, a=9; b=18; c=3; d=6.
a*b+c-d = 9*18+3-6 = 162+3-6 = 165-6 = 159.
Answer: 159
Ans 3:
Class : Class 4
sorry, 159 because a+b=27 b-a=9. Therefore a=18 b=9. d-c=3 and a+b+c+d=36 ab=27 so 36-27=9 d is bigger than c so d=6 c=3
a=18
b=9
c=3
d=6
final question a*b+c-d
18*9= 162
162+3=165
165-d or 165-6=159
ANSWER=159
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Ans 1:
Class : Class 9
the answer is 50.5.
it can be solved by :sum of the nos./no. of numbers.
by formula, sum of first 100 natural nos. is n*(n+1)/2=100*101/2=5050.
so answer comes out to be 5050/100=50.5
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Ans 1:
Class : Class 5
It was a mathematical calculation created by Pythagoras, to find out the hypotenuse of a right angled triangle. It is -:
Altitude[squared]+ Base[squared]= Hypotenuse[squared]
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