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Harshada Vyavhare from S.E.M.S, Shevgaon Tal. Shevgaon
Subject :IMO    Class : Class 8

Ans 1:

Sheetal from Dr. Pillai Global Academy, panvel
Class : Class 8
281.6

Ans 2:

Yash Mehta from GIIS, Singapore
Class : Class 8
281.6

Ans 3:

sparshgumasta from kvseoni, Seoni
Class : Class 8
281.6

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Harshada Vyavhare from S.E.M.S, Shevgaon Tal. Shevgaon
Subject :IMO    Class : Class 6

Ans 1:

Aditya Yadav from the bhavans prominent international, Indore
Class : Class 6
HOHOUFYDVJ,VJG

Ans 2:

Utkarsh from Podar International school, Ahmedabad
Class : Class 6
yeah the answer is 1000 trees. bro because see 4km 800m = 4800 by multiply we had converted it to metres to solve the sum. then step2= we will divide it to 9.6 because it has said to have intervals and to find the intervals we need to divide as we dont know how is the length is by after the interval and after the answer will be 500 step3= then the trees are planted both sides of the roads so multiply with or by 2 and the answer is 1000 trees.

Ans 3:

VANSH GUPTA from MDS SCHOOL , SEC -3, UDAIPUR, Udaipur
Class : Class 7
1000 trees

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Roma singh from RBK Global School, Maharashtra
Subject :IMO    Class : Class 7

Ans 1:

Romeyo Vivek from Mount litera zee school barh, Barh
Class : Class 7
(H)2=(P)2+(B) 2

Ans 2:

Janhavi Sawant from St.Andrew's high school, Pune
Class : Class 8
Hypotenuse=(side1)*2+(side2)*2

Ans 3:

riddhikaa from sri kumaran public school, Bengaluru
Class : Class 7
The pythagoras' theorem states that the square of the hypotenuse is equal to the sum of the square of the other 2 sides. The equation would be hyp2=S12+S22 note: the 2 is the power of two

Ans 4:

Prankush Bansal from St. Francis School , Shamli
Class : Class 7
A2+B2=C2

Ans 5:

KR. Aryan from DAV public school crrc medical unit gaya, Gaya
Class : Class 7
Hypotenuse=base×base+hieght×height Base=hypotenuse×hypotenuse -height ×height Height=base×base - hypotenuse×hypotenuse

Ans 6:

Manas Malla from Visakha Valley School, Visakhapatnam
Class : Class 8
Asquare+B square = C square (hypotenuse)

Ans 7:

Romeyo Vivek from Mount litera zee school barh, Barh
Class : Class 7
(H)2=(P)2+(B) 2

Ans 8:

Gyanepsaa from HUS International, Chennai
Class : Class 10
a = 1 side, b = another side, c = hypotenuse (the longest side). The formula is: a2 + b2 = c2 (the two means squared, not multiplied by two). The formula only works in right-angled triangles.

Ans 9:

ANSH from DAYANAND PUBLIC SCHOOL, SHIMLA
Class : Class 8
AB2+BC2=AC2 THIS MEANS THAT IN A TRIANGLE WHEN WE ADD THE SQUARE OF THE BASE AND PARALLEL ANGLE IT WILL ALWAYS BE EQUAL TO THE HYPOTENUSE.

Ans 10:

G. Priyanka from Chennai Public School, Chennai
Class : Class 8
square of base + square of perpendicular side = square of hypoteneuse

Ans 11:

nasr2607@gmail.com from Aurum the Global School, Haldwani
Class : Class 8
a2+b2=c2

Ans 12:

dev mishra from Bal Bhavan Public School, New Delhi
Class : Class 9
(H)2=(P)2+(B)2

Ans 13:

Karan from Dps Rohini, New Delhi
Class : Class 7
Square of hypotenuse=Square of its legs

Ans 14:

Romeyo Vivek from Mount litera zee school barh, Barh
Class : Class 7
(H)2=(P)2+(B) 2

Ans 15:

Gyanajyoti Mishra from J.N.V., Jajpur
Class : Class 10
Hypotenuse^2= P^2 + B^2 Here, P=perpendicular height and B=base.

Ans 16:

Tanishtha Gupta from Lancer's Convent school, New Delhi
Class : Class 9
square of hypotenuse=sum of square of other 2 legs in a right angled triangle

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dev mishra from Bal Bhavan Public School, New Delhi
Subject :IMO    Class : Class 7

Ans 1:

Manas Malla from Visakha Valley School, Visakhapatnam
Class : Class 8
If we multiply anything by 0, the answer is 0

Ans 2:

Prankush Bansal from St. Francis School , Shamli
Class : Class 7
-2

Ans 3:

dev mishra from Bal Bhavan Public School, New Delhi
Class : Class 9
Its a very big 000000000.................

Ans 4:

KR. Aryan from DAV public school crrc medical unit gaya, Gaya
Class : Class 7
(-2)-(2)(9)(0) =4(9)(0) =36(0) =0 ans.

Ans 5:

Manan Sharma from Naini Valley School, Kathgodam
Class : Class 7
0

Ans 6:

Sanchay from BIS Dwarka, Dwarka
Class : Class 8
A big,big 0!

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Kartavya Upendra Kalia from Akshara International School, Pune
Subject :IMO    Class : Class 1

Ans 1:

Sohum Saha from DAV Model School Durgapur, Durgapur
Class : Class 7
Change your password. Or create a new login with a different id.

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Ananth B from Yuvabharathi Public School, Coimbatore
Subject :IMO    Class : Class 7

Ans 1:

Sanchay from BIS Dwarka, Dwarka
Class : Class 8
X=-2 according to distributive law.

Ans 2:

Gyanepsaa from HUS International, Chennai
Class : Class 10
19x = -32

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Ananth B from Yuvabharathi Public School, Coimbatore
Subject :IMO    Class : Class 7

Ans 1:

Gyanepsaa from HUS International, Chennai
Class : Class 10
-1*27*-1*53*-1*4 = -5724

Ans 2:

Sanchay from BIS Dwarka, Dwarka
Class : Class 8
It means (-1)^[27+53+4] {That is a^m*a^n=a^(m+n)} =(-1)^74=1

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Ananth B from Yuvabharathi Public School, Coimbatore
Subject :IMO    Class : Class 7

Ans 1:

Gyanepsaa from HUS International, Chennai
Class : Class 10
Absolute value means you have to ignore the plus / minus sign. 4*7+3*(2-5) = 4*7+3-3 = 28

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Mohammad Shayaan Khan from BILLABONG, Bhopal
Subject :IMO    Class : Class 3

Ans 1:

Adithya Bharath M from Manipal School, Mangalore
Class : Class 7
1000

Ans 2:

Rayan Chanda from Salt Lake School, Kolkata
Class : Class 9
100

Ans 3:

suchir from dehli public school miyapur, Hyderabad
Class : Class 6
1000

Ans 4:

Dev Rawat from R D Rajpal School, New Delhi
Class : Class 8
1000

Ans 5:

Chaitanya Sharma from Nosegay Public School, Sri ganganagar
Class : Class 8
1000

Ans 6:

Navneeth Reejish from Yuvabharati International school, Singapore
Class : Class 7
1000

Ans 7:

Harshada Vyavhare from S.E.M.S, Shevgaon Tal. Shevgaon
Class : Class 3
The sucsessor of 999 is 1000.

Ans 8:

Chaitanya Sharma from Nosegay Public School, Sri ganganagar
Class : Class 8
1000

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Mohammad Shayaan Khan from BILLABONG, Bhopal
Subject :IMO    Class : Class 3

Ans 1:

Kashvi Priyadarshi from AVM Juhu, Mumbai
Class : Class 4
1000

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