Class : Class 9
let each pencil costs x. So 5 pencil costs 5x
Therefore 70-5x = y
or -5x= y-70
or 5x=70-y
or x= (70-y)/5
Class : Class 9
let each pencil costs x. So 5 pencil costs 5x
Therefore 70-5x = y
or -5x= y-70
or 5x=70-y
or x= (70-y)/5
Class : Class 9
let each pencil costs x. So 5 pencil costs 5x
Therefore 70-5x = y
or -5x= y-70
or 5x=70-y
or x= (70-y)/5
Ans 1:
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Ans 7:
Class : Class 8
Actually I checked in New Guided Mathematics book 5 and I got formula for answer is 2*(L*B). So you can refer to this book. KEY - *= multiplication sign; L= length; B=breadth
Ans 8:
Class : Class 8
Answer is correct but how? For this Question check the solution from SOF website or from your IMO Workbook. Actually I am not SOF and I myself did not understand how A
Ans 10:
Class : Class 9
The answer is A as the breadth of the rectangle is 2 cm. The length of the rectangle is 5 so 2 minus 5 is 3 and if we divide it into two parts it is 2 and 1. So we need to plus 2,2,2,1,2,1,1,2,1,2,2,2 for the answer. The answer after adding these numbers is 20
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Match the following.
column 1 | column 2 |
(p)171 taken away from 492 | (A)300 |
(q)26 removed from 596 | (B)281 |
(r)100 less than 400 | (C)321 |
(s)Difference between 392 and 111 | (D)570 |
A (p)→(C), (q)→ (D), (r)→ (B), (s)→ (A)
B (p)→(C), (q)→ (D), (r)→ (A), (s)→ (B)
C (p)→(C), (q)→ (A), (r)→ (D), (s)→ (B)
D (p)→(A), (q)→ (B), (r)→ (C), (s)→ (D)
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Ans 4:
Class : Class 8
The solution to this question is not correct. The solution is counting quadrilateral shapes as triangles.