International Maths Olympiad Forum By SOF Olympiad Trainer - Page 43
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Ayansh Mallick from Birla Open Minds, Hyderabad
Subject :IMO    Class : Class 6

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Avaneesh Barithaya from New Horizon Scholars School Vasant Lawns, Thane
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Ishani sahu from ST. Thomas Mission English School Jhalap, mahasamund
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Ishani sahu from ST. Thomas Mission English School Jhalap, mahasamund
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Antareep Mukherjee from New Horizon Public School, Bangalore
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Jeenal Gupta from Adani public school mundra, Mundra
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Shlok Deshaval from The Orbis School, Pune
Subject :IMO    Class : Class 10

Ans 1:

Tanya from Kensri, Bangalore
Class : Class 10
C. 4480 m VOLUME OF FRUSTUM= VOLUME OF WIRE (calculate radius using trigonometry) R=radius of original cone, H=height of original cone, r=radius of new cone, h=height of new cone, r₁²=radius of wire, h₁=height/length of wire vol. of frustum= vol. of original cone- vol. of smaller cone (cut off) => 1/3πR²H - 1/3πr²h => 1/3π*7000/3cm³ vol. of wire(cylinder) = πr₁²h₁ => π1/24*1/24*h equating and cancelling on both sides of equation, 7000= h/64 h=448000cm = 4480 m

Ans 2:

Tanya from Kensri, Bangalore
Class : Class 10
C. 4480 m VOLUME OF FRUSTUM= VOLUME OF WIRE (calculate radius using trigonometry) R=radius of original cone, H=height of original cone, r=radius of new cone, h=height of new cone, r₁²=radius of wire, h₁=height/length of wire vol. of frustum= vol. of original cone- vol. of smaller cone (cut off) => 1/3πR²H - 1/3πr²h => 1/3π*7000/3cm³ vol. of wire(cylinder) = πr₁²h₁ => π1/24*1/24*h equating and cancelling on both sides of equation, 7000= h/64 h=448000cm = 4480 m

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