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Post Your Answer
Post Your Answer
Ans 1:
Class : Class 2
Length of pen P = 10 Length of pen Q = 7 Length of pen R = 4 Length of pen S = 9 So, the required arrangement of pens fromthe longest to the shortest is P, S, Q, R.
Post Your Answer
Ans 1:
Class : Class 2
P. 182 246 134 = 562∴ Digit at tens place is 6.Q. 425 367 156 = 948∴ Digit at tens place is 4.R. 142 464 292 = 898∴ Digit at tens place is 9.S. 325 134 272 = 731∴ Digit at tens place is 3.∴ P → c, Q → a, R → d, S → b
Ans 2:
Class : Class 2
P. 182 246 134 = 562∴ Digit at tens place is 6.Q. 425 367 156 = 948∴ Digit at tens place is 4.R. 142 464 292 = 898∴ Digit at tens place is 9.S. 325 134 272 = 731∴ Digit at tens place is 3.∴ P → c, Q → a, R → d, S → b