International Maths Olympiad Forum By SOF Olympiad Trainer - Page 422
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Bindiya Bhoi from null, null
Subject :IMO    Class : Class 5

Ans 1:

Vatsala from DPS, Durg
Class : Class 8

Ans 2:

Samith Ramesh from New Horizon Gurukul, Bangalore
Class : Class 5

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Daksh Chanani from Sri Sri academy, Kolkata
Class : Class 7

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Bindiya Bhoi from null, null
Class : Class 4

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Harshita Jain from CCA School, Gurugram
Subject :IMO    Class : Class 5

Ans 1:

Arav Aanand from Father Agnel School, Noida
Class : Class 6
What is the number between 11 and 13 = 12 So it is B Others are false: I request you all to check your question and your answer

Ans 2:

Aarnav Grover from Anand Niketan Shilaj, Ahmedabad
Class : Class 9
easy B

Ans 3:

Harshita Jain from CCA School, Gurugram
Class : Class 6
sorry a

Ans 4:

ANGELA from new gulf indian, kuwait
Class : Class 7

Ans 5:

Harshita Jain from CCA School, Gurugram
Class : Class 6
it could be a or c to

Ans 6:

Harshita Jain from CCA School, Gurugram
Class : Class 6

Ans 7:

Harshita Jain from CCA School, Gurugram
Class : Class 6
but since it was after 11th that is why the answer was c

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Avantika Raj from Delhi Public School, Bengaluru
Subject :IMO    Class : Class 3

Ans 1:

Medhansh Sachdeva from Deens Academy, Bangalore
Class : Class 5
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Ans 2:

Ira from Sanskriti Hyderabad, Hyderabad
Class : Class 6

Ans 3:

Ira from Sanskriti Hyderabad, Hyderabad
Class : Class 6

Ans 4:

Avantika Raj from Delhi Public School, Bengaluru
Class : Class 9
answer is b

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Rishabh from Baala Balaga,
Subject :IMO    Class : Class 8

Given below are the steps of construction of a quadrilateral PQRS, where PQ = 5.5 cm, QR = 8.5 cm, ∠P = 75°,
∠Q = 105°, ∠R = 120°. Which of the following is a wrong step?
(i) Draw PQ = 5.5 cm.
(ii) Draw ∠XPQ = 75° at P and ∠PQY = 105° at Q.
(iii) With Q as centre and radius QR = 5.5 cm, draw an arc to intersect QY at R.
(iv) At R, draw ∠PSR = 120° such that RT meets PX at S.
PQRS is the required quadrilateral.

A(iii) only
B(ii) & (iv) only
C(iii) & (iv) only
D(iv) only


Confusing question. After step 3 is wrong, step 4 is wrong by definition

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Avantika Raj from Delhi Public School, Bengaluru
Subject :IMO    Class : Class 3

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Bindiya Bhoi from null, null
Subject :IMO    Class : Class 5

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Ami Buch from DPS Gandhinagar, Gandhinagar
Subject :IMO    Class : Class 8

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Aaryan from New horizons public school , Mumbai
Subject :IMO    Class : Class 8

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Kavinesh S from National Public School, Bangalore
Subject :IMO    Class : Class 3

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Samriddhi Debnath from Garden High School, Kolkata
Class : Class 3
1 apple 1orange =4200 g Therefore 2oranages 2apples =4200 g X 2=8400g Answer :A-8400g

Ans 2:

Sharodiya Ghosh from The New town school , Kolkata
Class : Class 3

Ans 3:

SHRESTA from JOHNSON GRAMMAR SCHOOL, Hyderabad
Class : Class 3
the pointers are not correct in the balance.

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Garv porwal from witty international school, Udaipur
Subject :IMO    Class : Class 4

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