ABCD is parallelogram, G is the point on AB such that AG = 2GB, E is point on DC such that CE = 2DE and F is the point on BC such that BF = 2FC. Then, match the following:
| Column-I | Column-II |
| P. ar (ADEG) | (i)  ar (ABCD) |
| Q. ar (∆EGB) | (ii) ar (∆EDG) |
| R. ar (∆EFC) | (iii) ar (GBCE) |
| S. ar (∆EGB) | (iv)  ar (∆EBF) |
| P | Q | R | S | |
| A | (i) | (ii) | (iii) | (iv) |
| B | (iii) | (i) | (iv) | (ii) |
| C | (iii) | (ii) | (iv) | (i) |
| D | (ii) | (i) | (iii) | (iv) |
Why cant it be C
