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Pragun goel from Venkateshwar International School, Delhi
Subject :IMO    Class : Class 5

Ans 1:

Arunava hury from KV1 saltlake , Kolkata
Class : Class 6
Option B)

Ans 2:

AREEN from BOLTON, HYDERABAD
Class : Class 6
Ans is B because 3645279+2153467=5798746. 5798746 will be rounded to its nearest ten thousand, which is 5800000, since 98746 will be rounded to nearest ten thousand, which is 100000, 1 will be carried to the lakhs place, or, you can say that 3645279 and 2153467 will be rounded to the nearest ten thousand, which will be 3650000 and 2150000, respectively. 3650000+2150000=5800000.

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Shruti Hegde from Mount Litera Zee school, Bengaluru
Subject :IMO    Class : Class 8

Ans 1:

Ishaan Pal from Christ Academy, Bangalore
Class : Class 9
ans is 4. (2,3,5,7)

Ans 2:

Pranav from Ganges valley school, Hyderabad
Class : Class 8
The answer is 3. When you solve the equation you get 3*3*1*1*2*14/1*1*1. Now we see that the prime numbers left are 3,3 and 2. Therefore there are 3 prime numbers.

Ans 3:

Pranav from Ganges valley school, Hyderabad
Class : Class 8
The answer is 3. When you solve the equation you get 3*3*1*1*2*14/1*1*1. Now we see that the prime numbers left are 3,3 and 2. Therefore there are 3 prime numbers.

Ans 4:

ARNAV BARANWAL from KPS SCHOOL, bhilai
Class : Class 4
ans is 7

Ans 5:

DEVRAJ DOLEY from NPS INTERNATIONAL SCHOOL, Guwahati
Class : Class 8
the answer is 7.

Ans 6:

svayumbhu sharma from jodhamal public school, jammu
Class : Class 9

Ans 7:

Aman Sumod from Chinmaya Vidyalaya, KANNUR
Class : Class 8
The answer is 4. There are 4 prime factors: 2,3,5 and 7

Ans 8:

Yuvraj Singh Dhaliwal from The British School, Patiala
Class : Class 8

Ans 9:

Ayush Gorain from Sarala Birla Public School, Ranchi
Class : Class 8
The answer should be option (A) = 4. There are 4 prime factors, i.e. 2, 3, 5 and 7. The solution contradicts the question's answer.

Ans 10:

Hari Bhaskar from bgs, JP Nagar 7th Phase
Class : Class 6
the solution of the equation is 3*3*5*5*5*2*7 which has seven prime factors

Ans 11:

Angshu from Dehli Public School Bangalore East, Bangalore
Class : Class 9
The answer should be (A) 4.There are four factors, i.e. 2,3,5,7. Even the solution says so. Please correct the error.

Ans 12:

Shreya Shruti from Airforce school , Bengaluru
Class : Class 8
the answer is 4!!!

Ans 13:

Ashwin Shridhar from Vidyashilp Academy, Bangalore
Class : Class 9
4

Ans 14:

Akshara from NPS, Bengaluru
Class : Class 8
Yes .... The answer is 4. ( 2, 3 ,5 and 7)

Ans 15:

Mohammed Aatif Afnan from Phoenix Greens School of Learning, Hyderabad
Class : Class 8
The answer is 4, not 3

Ans 16:

Mudit garg from La blossoms school, Jalandhar
Class : Class 7

Ans 17:

jayashree easwaran from vibgyor High, Bengaluru
Class : Class 4
isn't the answer "A"

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Advait nagale from Universal High, Thane
Subject :IMO    Class : Class 3

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Mayank Paul from Saint Edmunds School, Shillong
Subject :IMO    Class : Class 3

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Ankit Kumar Mistry from Kalyani Public School, Kolkata
Subject :IMO    Class : Class 4

Ans 1:

Nehal from New Horizon Gurukul, Bangalore
Class : Class 6

Ans 2:

Aharshi Sarkar from Venkateshwar International School Dwarka, Delhi
Class : Class 5
The answer is (A) because it has said the minor 5-digit no.

Ans 3:

Midhuna from ABCD, Banglore
Class : Class 3

Ans 4:

Satvik Agrawal from Delhi Public School, bhopal
Class : Class 5
dfd

Ans 5:

Sweta from dpsnoida, Noida
Class : Class 4
solutions should be in detail and a little easy

Ans 6:

Ashwak from Cambridge, Jalandhar
Class : Class 9
The answer is D .

Ans 7:

Ashwak from Cambridge, Jalandhar
Class : Class 9
BIR you have written ten thousand instead of one thousand !!!

Ans 8:

Soumya Gupta from Prudence School Ashok Vihar, New Delhi
Class : Class 5
the answer is c

Ans 9:

Sarah Ahmad from st. mary's school, delhi
Class : Class 7

Ans 10:

MANDAR PALKAR from KV DRDO, Bengaluru
Class : Class 2
100 tens = 1 thousand

Ans 11:

BIR from LOTUS VALLEYINTERNATIONAL SCHOOL, NOIDA
Class : Class 4
10000

Ans 12:

Shreeya Mangla from ASN Senior Secondary School, New Delhi
Class : Class 8

Ans 13:

Shraddha from Delhi public school, Hyderabad
Class : Class 4
The answer is D

Ans 14:

Sarah Ahmad from st. mary's school, delhi
Class : Class 7
The answer is D- 1 thousand

Ans 15:

Amartya Dey from DPS Bangalore East, Bangalore
Class : Class 6
trick question

Ans 16:

Sarthak Shome from Harvest International, Bangalore
Class : Class 7
man the answer is 10 lackhs

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Astha Aswani from Fatima convent school, Kanpur
Subject :IMO    Class : Class 8

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DEVANSHI R SHAH from DIVYAPATH CAMPUS, AHMEDABAD
Subject :IMO    Class : Class 7

Ans 1:

Arshia Mittal from Ryan International School, rohini
Class : Class 9
its more than easy D

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rachana from delhi public school, NACHARAM
Subject :IMO    Class : Class 3

Ans 1:

Arpit Gupta from Treamis World School, Bengaluru
Class : Class 5
options given seems to be wrong

Ans 2:

Krishang Roushan from Dimension International College, Singapore
Class : Class 3
It is not that hard, just that if you understand the question you can easily find the answer.The pea pie who are saying that the question is wrong, you are the one who is wrong, not the question!

Ans 3:

Aamogh from Kv, Chennai
Class : Class 3
correct answer should be 33

Ans 4:

Anaisha Niranjan from DPS Noida, Noida
Class : Class 4
the answer should 107

Ans 5:

Aditya Mittal from St Peters College, AGRA
Class : Class 5
It is not wrong moon divide by star is 3 moon multiply by moon is 324 3star multiply 3star is 324 star .star equals 324/9 is 36 star - 6 moon equals 18 answer is 12

Ans 6:

Raghav from Gems wellington school, Doha
Class : Class 6
it is a little tricky but i solved it.

Ans 7:

IAMLOST from ABC, Pune
Class : Class 8
It is NOT out of syllabus . The sulution is that one moon is 18.So,18x18=324.To get the star devide 18 by 3=6.18-6=12

Ans 8:

Chanchal Sharma from Universal high School, Thane West
Class : Class 3

Ans 9:

Suchi shah from AIS, Ahmedabad
Class : Class 3
pls explain

Ans 10:

Krishna Nanda from St. Xaviers Co Ed School Bhopal, Bhopal
Class : Class 7
the answer is 108

Ans 11:

Harshith from Cs academy, Erode
Class : Class 3

Ans 12:

Rajdeep Chatterjee from Techno India Public School, Bolpur
Class : Class 8
IT IS OUT OF SYLLABUS.

Ans 13:

Jeremy Sen from Montfort Senior Secondary, Roorkee
Class : Class 5
wat

Ans 14:

AARAV GUPTA from Khaitan Public School, Ghaziabad
Class : Class 4
Out of Syllabus

Ans 15:

Suchi shah from AIS, Ahmedabad
Class : Class 3
How the value of 2 moon is 18 i think 324/2=162

Ans 16:

Prisha Jora from Adani Public School, Mundra
Class : Class 3
I don't know the answer because IT IS OUT OF SYLLABUS

Ans 17:

AARAV GUPTA from Khaitan Public School, Ghaziabad
Class : Class 4

Ans 18:

Vihaan Agrawal from DG Agrawal memorial school , Visarwadi
Class : Class 3
I think, it is too much to ask 3rd class student to remember squares of 18.. imagine if kid is not able to identify m * m = 324, how would he be able to solve entire question. not fair!!

Ans 19:

princy gigo from Global Indian International School, Kuala Lumpur
Class : Class 8
out of syallabus

Ans 20:

Aanya from Apeejay School , Delhi
Class : Class 7

Ans 21:

Inaaya Garg from Carmel Convent School, Chandigarh
Class : Class 4

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Sanskriti Samant from Euroschool Wakad, Pune
Subject :IMO    Class : Class 4

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Chiranjib kar from MOUNT LITERA ZEE SCHOOL, JAJPUR
Subject :IMO    Class : Class 5

Study the given line graph which shows the capacity of petrol Mohit used while travelling from City X to City Y from April to August and answer the following questions.

(A) How much more capacity of petrol was used in August than in May?
(B) What fraction of the total capacity of petrol used in July?

(A) (B)
A 20000 mL 7/26
B 22000 mL 8/29
C 10000 mL 7/27
D 25000 mL 9/36


Ans not understood... I doubt if the ans is correct.

Ans 1:

AREEN from BOLTON, HYDERABAD
Class : Class 6
Ans is A because the answer of question (A) will be 20000 ml because 40 l-20 l=20 l. Now convert 20 l to ml, which is 20000 ml, or, you can say that 20 l and 40 l will be 20000 ml and 40000 ml, respectively. Now do 20000 ml-40000 ml=20000ml. answer of question (B) will be 7/26 by adding the capacity of petrol of April, May, June, July and August, which will be 10 l+20 l+ 25 l+35 l+40 l=130 l. In July, the capacity of petrol used was 35 l, so in fraction, it will be 35 l/130 l. Now simplify the fraction, which will be 7 l/26 l.

Ans 2:

Arunava hury from KV1 saltlake , Kolkata
Class : Class 6
Option A)

Ans 3:

Arav Gupta from Devagiri CMI PUBLIC SCHOOL, Kozhikode
Class : Class 4
There is no need to do the second part.The first answer is 20L which is 20,000ml. And there is only one option with that answer, which is A,

Ans 4:

Vivaan Singh from Salwan Junior School, NEW DELHI
Class : Class 5

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