International Maths Olympiad Forum By SOF Olympiad Trainer - Page 554
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Prachi from Holy Child Public school, Faridabad
Subject :IMO    Class : Class 4

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Pragun goel from Venkateshwar International School, Delhi
Subject :IMO    Class : Class 5

Ans 1:

Arunava hury from KV1 saltlake , Kolkata
Class : Class 6
Option B)

Ans 2:

AREEN from BOLTON, HYDERABAD
Class : Class 6
Ans is B because 3645279+2153467=5798746. 5798746 will be rounded to its nearest ten thousand, which is 5800000, since 98746 will be rounded to nearest ten thousand, which is 100000, 1 will be carried to the lakhs place, or, you can say that 3645279 and 2153467 will be rounded to the nearest ten thousand, which will be 3650000 and 2150000, respectively. 3650000+2150000=5800000.

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Shruti Hegde from Mount Litera Zee school, Bengaluru
Subject :IMO    Class : Class 8

Ans 1:

Pranav from Ganges valley school, Hyderabad
Class : Class 8
The answer is 3. When you solve the equation you get 3*3*1*1*2*14/1*1*1. Now we see that the prime numbers left are 3,3 and 2. Therefore there are 3 prime numbers.

Ans 2:

Hari Bhaskar from bgs, JP Nagar 7th Phase
Class : Class 6
the solution of the equation is 3*3*5*5*5*2*7 which has seven prime factors

Ans 3:

Yuvraj Singh Dhaliwal from The British School, Patiala
Class : Class 8

Ans 4:

jayashree easwaran from vibgyor High, Bengaluru
Class : Class 4
isn't the answer "A"

Ans 5:

svayumbhu sharma from jodhamal public school, jammu
Class : Class 9

Ans 6:

Ishaan Pal from Vibgyor HSR, Bangalore
Class : Class 9
ans is 4. (2,3,5,7)

Ans 7:

Shreya Shruti from Airforce school , Bengaluru
Class : Class 8
the answer is 4!!!

Ans 8:

Ashwin Shridhar from Vidyashilp Academy, Bangalore
Class : Class 9
4

Ans 9:

Ayush Gorain from Sarala Birla Public School, Ranchi
Class : Class 8
The answer should be option (A) = 4. There are 4 prime factors, i.e. 2, 3, 5 and 7. The solution contradicts the question's answer.

Ans 10:

Akshara from NPS, Bengaluru
Class : Class 8
Yes .... The answer is 4. ( 2, 3 ,5 and 7)

Ans 11:

Mohammed Aatif Afnan from Phoenix Greens School of Learning, Hyderabad
Class : Class 8
The answer is 4, not 3

Ans 12:

Angshu from Dehli Public School Bangalore East, Bangalore
Class : Class 9
The answer should be (A) 4.There are four factors, i.e. 2,3,5,7. Even the solution says so. Please correct the error.

Ans 13:

Pranav from Ganges valley school, Hyderabad
Class : Class 8
The answer is 3. When you solve the equation you get 3*3*1*1*2*14/1*1*1. Now we see that the prime numbers left are 3,3 and 2. Therefore there are 3 prime numbers.

Ans 14:

Aman Sumod from Chinmaya Vidyalaya, KANNUR
Class : Class 8
The answer is 4. There are 4 prime factors: 2,3,5 and 7

Ans 15:

Mudit garg from La blossoms school, Jalandhar
Class : Class 7

Ans 16:

DEVRAJ DOLEY from NPS INTERNATIONAL SCHOOL, Guwahati
Class : Class 8
the answer is 7.

Ans 17:

AANYA BARANWAL from KPS SCHOOL, bhilai
Class : Class 5
ans is 7

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Advait nagale from Universal High, Thane
Subject :IMO    Class : Class 3

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Mayank Paul from Saint Edmunds School, Shillong
Subject :IMO    Class : Class 3

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Ankit Kumar Mistry from Kalyani Public School, Kolkata
Subject :IMO    Class : Class 4

Ans 1:

MANDAR PALKAR from KV DRDO, Bengaluru
Class : Class 2
100 tens = 1 thousand

Ans 2:

Shreeya Mangla from ASN Senior Secondary School, New Delhi
Class : Class 9

Ans 3:

BIR from LOTUS VALLEYINTERNATIONAL SCHOOL, NOIDA
Class : Class 4
10000

Ans 4:

Ashwak from Cambridge, Jalandhar
Class : Class 9
BIR you have written ten thousand instead of one thousand !!!

Ans 5:

Satvik Agrawal from Delhi Public School, bhopal
Class : Class 5
dfd

Ans 6:

Sweta from dpsnoida, Noida
Class : Class 4
solutions should be in detail and a little easy

Ans 7:

Nehal from New Horizon Gurukul, Bangalore
Class : Class 6

Ans 8:

Sarah Ahmad from st. mary's school, delhi
Class : Class 8

Ans 9:

Aharshi Sarkar from Venkateshwar International School Dwarka, Delhi
Class : Class 6
The answer is (A) because it has said the minor 5-digit no.

Ans 10:

Shraddha from Delhi public school, Hyderabad
Class : Class 4
The answer is D

Ans 11:

Soumya Gupta from Prudence School Ashok Vihar, New Delhi
Class : Class 5
the answer is c

Ans 12:

Amartya Dey from DPS Bangalore East, Bangalore
Class : Class 7
trick question

Ans 13:

Sarthak Shome from Harvest International, Bangalore
Class : Class 8
man the answer is 10 lackhs

Ans 14:

Sarah Ahmad from st. mary's school, delhi
Class : Class 8
The answer is D- 1 thousand

Ans 15:

Midhuna from ABCD, Banglore
Class : Class 3

Ans 16:

Ashwak from Cambridge, Jalandhar
Class : Class 9
The answer is D .

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Astha Aswani from Fatima convent school, Kanpur
Subject :IMO    Class : Class 8

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DEVANSHI R SHAH from DIVYAPATH CAMPUS, AHMEDABAD
Subject :IMO    Class : Class 7

Ans 1:

Arshia Mittal from Ryan International School, rohini
Class : Class 9
its more than easy D

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rachana from delhi public school, NACHARAM
Subject :IMO    Class : Class 3

Ans 1:

Prisha Jora from Adani Public School, Mundra
Class : Class 3
I don't know the answer because IT IS OUT OF SYLLABUS

Ans 2:

AARAV GUPTA from Khaitan Public School, Ghaziabad
Class : Class 4

Ans 3:

Krishna Nanda from St. Xaviers Co Ed School Bhopal, Bhopal
Class : Class 7
the answer is 108

Ans 4:

Krishang Roushan from Dimension International College, Singapore
Class : Class 3
It is not that hard, just that if you understand the question you can easily find the answer.The pea pie who are saying that the question is wrong, you are the one who is wrong, not the question!

Ans 5:

Aditya Mittal from St Peters College, AGRA
Class : Class 5
It is not wrong moon divide by star is 3 moon multiply by moon is 324 3star multiply 3star is 324 star .star equals 324/9 is 36 star - 6 moon equals 18 answer is 12

Ans 6:

AARAV GUPTA from Khaitan Public School, Ghaziabad
Class : Class 4
Out of Syllabus

Ans 7:

Harshith from Cs academy, Erode
Class : Class 3

Ans 8:

Anaisha Niranjan from DPS Noida, Noida
Class : Class 4
the answer should 107

Ans 9:

Aamogh from Kv, Chennai
Class : Class 3
correct answer should be 33

Ans 10:

Jeremy Sen from Montfort Senior Secondary, Roorkee
Class : Class 6
wat

Ans 11:

Aanya from Apeejay School , Delhi
Class : Class 7

Ans 12:

Suchi shah from AIS, Ahmedabad
Class : Class 3
How the value of 2 moon is 18 i think 324/2=162

Ans 13:

Inaaya Garg from Carmel Convent School, Chandigarh
Class : Class 4

Ans 14:

Suchi shah from AIS, Ahmedabad
Class : Class 3
pls explain

Ans 15:

Vihaan Agrawal from DG Agrawal memorial school , Visarwadi
Class : Class 3
I think, it is too much to ask 3rd class student to remember squares of 18.. imagine if kid is not able to identify m * m = 324, how would he be able to solve entire question. not fair!!

Ans 16:

princy gigo from Global Indian International School, Kuala Lumpur
Class : Class 8
out of syallabus

Ans 17:

IAMLOST from ABC, Pune
Class : Class 8
It is NOT out of syllabus . The sulution is that one moon is 18.So,18x18=324.To get the star devide 18 by 3=6.18-6=12

Ans 18:

Chanchal Sharma from Universal high School, Thane West
Class : Class 3

Ans 19:

Raghav from Gems wellington school, Doha
Class : Class 6
it is a little tricky but i solved it.

Ans 20:

Rajdeep Chatterjee from Techno India Public School, Bolpur
Class : Class 8
IT IS OUT OF SYLLABUS.

Ans 21:

Arpit Gupta from Treamis World School, Bengaluru
Class : Class 5
options given seems to be wrong

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Sanskriti Samant from Euroschool Wakad, Pune
Subject :IMO    Class : Class 4

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