International Maths Olympiad Forum By SOF Olympiad Trainer - Page 349
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Advika Narkar from The Shishukunj International School, Jhalaria Campus, Indore
Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

The correct answer is option D. 


Ans 2:

Adrito Roy from Stem world School, Kolkata
Class : Class 3

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Aarya Bhagwat from Aaryans World School, Pune
Subject :IMO    Class : Class 5

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B):

Length of pole painted red = 1.8 m
∴ Length of pole painted white = 3 × 1.8
= 5.4 m
So, total length of pole = (1.8 + 5.4)m = 7.2 m


Ans 2:

Avyukth Radhakrishnan from TSRS, Gurgaon
Class : Class 10

Ans 3:

Saipriya from Sankara, Chennai
Class : Class 8
yes admin master u r right

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DIYA NOBY from VISWAJYOTHI CMI PUBLIC SCHOOL, ANGAMALY
Subject :IMO    Class : Class 7

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N Khanna from MJKPS, New Delhi
Subject :IMO    Class : Class 6

Ans 1:

Shivesh Senthilkumar from vels vidyashram, chennai
Class : Class 6

Ans 2:

SOMRAJ HAZRA from Modern Delhi Public School, Faridabad
Class : Class 7
a is the answer simply do what ask add all the numbers

Ans 3:

Shivesh Senthilkumar from vels vidyashram, chennai
Class : Class 6

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Advika Narkar from The Shishukunj International School, Jhalaria Campus, Indore
Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B):

Number of chocolates Nimisha bought altogether = Number of chocolate boxes bought x Number of chocolates in each box
= 3 x 8 = 24


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Devang Shukla from Ryan Christian School, Mumbai
Subject :IMO    Class : Class 8

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ARADHYAA SHARMA from KULACHI HANS RAJ, delhi
Subject :IMO    Class : Class 1

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B):


Total number of triangles = 12
Total number of squares = 4
So, there are (12 – 4) = 8 more triangles than squares.


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Naman Sharma from SB PATIL PUBLIC SCHOOL, Pune
Subject :IMO    Class : Class 9

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NYRAH GUPTA from Sat Paul Mittal School, Ludhiana
Subject :IMO    Class : Class 6

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B): (P) Total number of equal parts = 7
Number of shaded parts = 4
∴ Shaded fraction = 4/7
(Q) Total number of equal parts = 8
Number of shaded parts = 5
∴ Shaded fraction = 5/8
(R) Total number of equal parts = 11
Number of shaded parts = 5
∴ Shaded fraction = 5/11
(S) Total number of equal parts = 9
Number of shaded parts = 5
∴ Shaded fraction = 5/9
Thus, the ascending order of shaded
fraction is 5/11, 5/9, 4/7, 5/8, i.e., R, S, P, Q


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SIDDHARTH SOMANI from Vibgyor High, Mumbai
Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B):

Square is not present in the given figure.


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