International Maths Olympiad Forum By SOF Olympiad Trainer - Page 349
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Pratham Dave from GNS, Bangalore
Subject :IMO    Class : Class 5

Ans 1:

Rishabh Jha from sandipani, Nagpur
Class : Class 7
A is Answer

Ans 2:

Rishabh Jha from sandipani, Nagpur
Class : Class 7
A is Answer

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Pratham Dave from GNS, Bangalore
Subject :IMO    Class : Class 5

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Arnav Raj Sharma from GEMS International School the ultra master mega, Gurgaon
Subject :IMO    Class : Class 7

Ans 1:

Aniket kumar from kendriya vidyalaya, Delhi
Class : Class 8

Ans 2:

Prateeshtha Ghosh from Samhita Academy, Bangalore
Class : Class 8
Even I think the answer should be 1/2

Ans 3:

Rudra modi from Krishna international public school, Patan
Class : Class 7
Answer should be 1/2

Ans 4:

Arnav Raj Sharma from GEMS International School the ultra master mega, Gurgaon
Class : Class 7
answer is 1/2

Ans 5:

AISHA from K.V.No.-1,A.F.S.,SEC.-14, GURUGRAM
Class : Class 10
YES,ANSWER IS 1/2

Ans 6:

AARAV AGRAWAL from BIRLA DIVYA JYOTI, SILIGURI
Class : Class 8
1/2

Ans 7:

LAVANYA DADHWAL from BLOOM PUBLIC SCHOOL, South West Delhi
Class : Class 8
The answer must be 1/2in two coins there are total 4 possibilities of head n tailout of which 2 possibilities are of tail hence it'll be 2/4 which is equal to 1/2

Ans 8:

Arnav Raj Sharma from GEMS International School the ultra master mega, Gurgaon
Class : Class 7

Ans 9:

Darsh Jain from The Vedansh International School, Indore
Class : Class 7
the answer is 3/4 because there are 4 possibilities - heads

Ans 10:

Hritvi from Podar International School, Mumbai
Class : Class 7
Answer should be 1/2.

Ans 11:

Ambati Daivik from Kendriya Vidyalaya, Dharwad
Class : Class 10

Ans 12:

Bhavtosh Tripathi from Maneckji Cooper Education Trust School, Mumbai
Class : Class 9
The answer should be B since getting at least one tail has a probability of 2/4 and simplifying it we will get 1/2

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Mohnish from Mm, m
Subject :IMO    Class : Class 7

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Gunnit Kant from DPS, Nerul, Navi Mumbai
Subject :IMO    Class : Class 4

Ans 1:

Gunnit Kant from DPS, Nerul, Navi Mumbai
Class : Class 5
B

Ans 2:

Hareesh venkatesh from Smt Ramkumari Fomra Vivekananda Vidyalaya, Chennai
Class : Class 5
B is the answer

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dveep jain from mindful gurukul, Mumbai
Subject :IMO    Class : Class 4

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dveep jain from mindful gurukul, Mumbai
Subject :IMO    Class : Class 4

Ans 1:

dveep jain from mindful gurukul, Mumbai
Class : Class 4
Answer is c

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Aayush Tripathy from SAI International School, Bhubaneswar
Subject :IMO    Class : Class 6

Ans 1:

Kanishk Mukherjee from BDM International, Kolkata
Class : Class 6
5/15+5/15+1/15=11/15 2/15+4/15+5/15=11/15 1/15+8/15+2/15=11/15 So the answer is D

Ans 2:

Tanish from New horizon, Bangalore
Class : Class 8
Answer is d

Ans 3:

AVANI THEKKEKARE from Npsi, Singapore
Class : Class 6
The correct answer is D

Ans 4:

AVANI THEKKEKARE from Npsi, Singapore
Class : Class 6

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Dhanya Shree K Y from Vssips, Bangalore
Subject :IMO    Class : Class 3

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1

(B): Total number of packets bought in March and April = 183
Total number of days in March and April  = 31 + 30 = 61
Packet bought on one day  = Total packets ÷ total days = 183 ÷ 61 = 3
Total packets bought in March =  3 × 31 = 93


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arohi from St francis school, Anpara
Subject :IMO    Class : Class 7

Ans 1:

Aditya Kadarapura from BGS NPS, Bangalore
Class : Class 7
96

Ans 2:

Aarushi10 Kataria from Modern High School for Girls, kolkata
Class : Class 8

Ans 3:

Paridhi Umesh Kumar from Seven Square Academy, Thane
Class : Class 7

Ans 4:

Sarang Shete from Amanora School, Pune
Class : Class 8
it says now, that means that the number of students which were there number of students added. Thus, 91 5 = 96

Ans 5:

shaurya gautam from Delhi Public School R.K. Puram, New Delhi
Class : Class 7

Ans 6:

Paridhi Umesh Kumar from Seven Square Academy, Thane
Class : Class 7
Even I got the answer as 96

Ans 7:

AISHA from K.V.No.-1,A.F.S.,SEC.-14, GURUGRAM
Class : Class 10
I ALSO GOT ANSWER AS 96.

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