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nimay gupta from Shiv Nadar School, noida
Subject :IMO    Class : Class 7

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VANSH PAMNANI from CAREER POINT WORLD SCHOOL, BILASPUR
Subject :IMO    Class : Class 6
Q

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VANSH PAMNANI from CAREER POINT WORLD SCHOOL, BILASPUR
Subject :IMO    Class : Class 6
Q

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Madhuranjan from Kvs , Sulur
Subject :IMO    Class : Class 3

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Ananya from Delhi public school Ghaziabad, Ghaziabad
Subject :IMO    Class : Class 4

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Agastya Tripathi from dps gurgaon, Gurgaon
Subject :IMO    Class : Class 6

Ans 1:

Saidutta Sidhesh S M from RN PODAR, Mumbai
Class : Class 10

Ans 2:

Aashish Jitendra Kumar from DPS Noida, Noida
Class : Class 6
how the above 3 has line of symmetry , It's lower part is bigger than above one

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from ,
Subject :IMO    Class : Class 3

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Aaditya Singh from Narrayana , Nallasopara
Subject :IMO    Class : Class 6

Ans 1:

Pratheek from Null, Null
Class : Class 4
60 degrees

Ans 2:

Nandu from The Asian School, Bahrain
Class : Class 3

Ans 3:

sakshi from podar international school , mumbai
Class : Class 1
60

Ans 4:

Yashraj Namdev Deshmukh from Sahyadri English School, Loha, Nanded
Class : Class 7

Ans 5:

Rayansh Mishra from VIBGYOR HIGH MAGARPATTA, Pune
Class : Class 8
whe

Ans 6:

sakshi from podar international school , mumbai
Class : Class 1

Ans 7:

Nikhil Bewal from APS KIRKEE, PUNE
Class : Class 6

Ans 8:

Avyukt Agarwal from Dps mathura road, Delhi
Class : Class 6

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HIMANI CHOURASIA from ALMAREEFA INTERNATIONAL SCHOOL, Jazan
Subject :IMO    Class : Class 5

Ans 1:

Soumyaraj Roy from Kendriya Vidyalaya , Thiruvananthapuram
Class : Class 7
You have to count only the squares which are shaded half or more than a half .

Ans 2:

Asmi Raniga from Indian school Ghubra, Muscat
Class : Class 7
how to do this?

Ans 3:

alankar from the palace school, Jaipur
Class : Class 1
36.5cm2

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HIMANI CHOURASIA from ALMAREEFA INTERNATIONAL SCHOOL, Jazan
Subject :IMO    Class : Class 5

Ans 1:

Dhaivat Bhatti from KES SMVM School, Mumbai
Class : Class 8
can you please tell me how you got 19. Harshit Solanki from Dps, Indore.area of 1 small rectangle = 3*2 =6 sq. cm.Total cards removed = 19 so ,19*6= 114 sq. cm.

Ans 2:

Aananya Singh from DPS East, Bangalore
Class : Class 4
Can you please explain the answer ?

Ans 3:

Ayush Pal from GD Goenka Public School Dakshineswar, West Bengal, India, Kolkata
Class : Class 8

Ans 4:

Vivaan from RN podar chool, Mumbai
Class : Class 5

Ans 5:

HARSHIT SOLANKI from Dps, Indore
Class : Class 6
area of 1 small rectangle = 3*2 =6 sq. cm.Total cards removed = 19 so ,19*6= 114 sq. cm.

Ans 6:

Aananya Singh from DPS East, Bangalore
Class : Class 4

Ans 7:

Advaith m from New horizon public school, Bangalore
Class : Class 4
HOW DID YOU GET 19 rectangles

Ans 8:

Aaditva from Vasant Valley School, New Delhi
Class : Class 8

Ans 9:

HARSHIT SOLANKI from Dps, Indore
Class : Class 6

Ans 10:

Jeremy Sen from Montfort Senior Secondary, Roorkee
Class : Class 5
duuuuuumb solution

Ans 11:

Avani Dixit from Elpro International School , PUNE
Class : Class 7

Ans 12:

stavya from dps noida, noida
Class : Class 6

Ans 13:

stavya from dps noida, noida
Class : Class 6
please tell me how do you guys know that 19 rectangles were removed.

Ans 14:

SOUVAGYA SAHA from De Nobili School, DHANBAD
Class : Class 10

Ans 15:

Souradeepto Das Mandal from Hyderabad Public School, Hyderabad
Class : Class 6
bro the small square at the is an rectangle and the thing is 2 rectangle so 19 square(rectangle) are there

Ans 16:

Vrinda Yadav from LVIS, Noida
Class : Class 5
Figure is not proper.

Ans 17:

Souradeepto Das Mandal from Hyderabad Public School, Hyderabad
Class : Class 6
so B is the answer

Ans 18:

Swarnava Pal from Vivekananda Mission School, Haldia
Class : Class 8
but the figure is not proper .

Ans 19:

HARSHIT SOLANKI from Dps, Indore
Class : Class 6

Ans 20:

SHRADHA MOHAPATRA from APEEJAY SCHOOL, New Delhi
Class : Class 5

Ans 21:

Pratham Dave from GNS, Bangalore
Class : Class 7
B is the answer to this question , Swarnava Pal

Ans 22:

Aarna Gupta from DPS EAST, BANGALORE , Bengaluru
Class : Class 8

Ans 23:

Arav Gupta from Delhi Public School Gurgaon, Gurgaon
Class : Class 8
I can explain those squares you see? sof refers to them by saying small rectangles. 5are in moth

Ans 24:

SHOURYA JANA from Birla High School Mukundapur, Kolkata
Class : Class 5
To solve this, let’s analyze the problem step-by-step: Find the area of a single small rectangle: Each small rectangle has a length of 3 cm and a breadth of 2 cm. So, the area of one small rectangle is: 3   cm × 2   cm = 6   sq. cm 3cm×2cm=6sq. cm Calculate the total area of all 81 small rectangles in the big rectangle: If there are 81 small rectangles, then the area of the big rectangle is: 81 × 6   sq. cm = 486   sq. cm 81×6sq. cm=486sq. cm Count the number of small rectangles remaining in the figure: From the image, we can count the number of small rectangles remaining. By visually inspecting, there appear to be 62 small rectangles left. Calculate the area of the remaining rectangles: With 62 rectangles remaining, the area of the remaining part is: 62 × 6   sq. cm = 372   sq. cm 62×6sq. cm=372sq. cm Find the total area of the rectangles removed: Subtract the area of the remaining rectangles from the total area to find the area of the removed rectangles: 486   sq. cm − 372   sq. cm = 114   sq. cm 486sq. cm−372sq. cm=114sq. cm Thus, the total area of the rectangles removed is 114 sq. cm. The correct answer is B) 114 sq. cm.

Ans 25:

Sowmya Chandrasekaran from DAV GIRLS SENIOR SECONDARY SCHOOL, Chennai
Class : Class 6

Ans 26:

Ishan sandip chaudhari from Divine Child International School, Ahmedabad
Class : Class 5
Bis the answer

Ans 27:

Suresh Gyanchandani from St. Anselms Pink City Senior Secondary School, Jaipur
Class : Class 5
14 rectangles are removed not 19 because figure is not proper

Ans 28:

Soumyaraj Roy from Kendriya Vidyalaya , Thiruvananthapuram
Class : Class 7

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