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if 1 + cot2θ = 
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Ans 1:
Class : Class 6
Solution(P) Total number of equal parts = 12 Number of shaded parts = 6 Shaded ratio = 6 : 12 = 1 : 2 (Q) Total number of equal parts = 8 Number of shaded parts = 4 Shaded ratio = 4 : 8 = 1 : 2 (R) Total number of equal parts = 10 Number of shaded parts = 6 Shaded ratio = 6 : 10 = 3 : 5 (Q) Total number of equal parts = 13 Number of shaded parts = 7 Shaded ratio = 7 : 13 Solution(P) Total number of equal parts = 12 Number of shaded parts = 6 Shaded ratio = 6 : 12 = 1 : 2 (Q) Total number of equal parts = 8 Number of shaded parts = 4 Shaded ratio = 4 : 8 = 1 : 2 (R) Total number of equal parts = 10 Number of shaded parts = 6 Shaded ratio = 6 : 10 = 3 : 5 (Q) Total number of equal parts = 13 Number of shaded parts = 7 Shaded ratio = 7 : 13
Ans 3:
Class : Class 8
How can 2 things in column 1 be equal to one thing in column 2? There was no mention that this is possible. Please rectify SOF
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Find the values of P, Q, R and S.
| P | Q | R | S | |
| A | 12 | 74 | 15 | 207 |
| B | 12 | 15 | 74 | 270 |
| C | 12 | 74 | 15 | 270 |
| D | 42 | 15 | 270 | 74 |
c
