International Maths Olympiad Forum By SOF Olympiad Trainer - Page 752
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S SIVASHAILESH from CHETTINAD VIDHYASHRAM, Chennai
Subject :IMO    Class : Class 3

Ans 1:

Dhairya Godbole from KLE Eng Medium School, SOLAPUR
Class : Class 6
Even I had raised the same question on forum. I could not find ny logic in the answer given.

Ans 2:

Ridhan from SFS janakpuri, New Delhi
Class : Class 5
It is correct but tough one

Ans 3:

Aaditya from Mayoor School, Noida
Class : Class 3
I think the diagram / picture is missing, only question is there in the sheet

Ans 4:

Soham Gupta from JSSIS Dubai, Dubai
Class : Class 6
even I asked the same didn't understand

Ans 5:

Advika Katiyar from DPS, Indore
Class : Class 3

Ans 6:

Aryan Goyal from DPS , Dwarka, New Delhi
Class : Class 3
wrong question

Ans 7:

Aarush from CA, Bengaluru
Class : Class 5
no relation between question and solution provided

Ans 8:

Elina from BASELIOUS PUBLIC SCHOOL, Gujarat refinery
Class : Class 2
No logic in this sum

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archana shaji from nps , Bengaluru
Subject :IMO    Class : Class 3

Ans 1:

Aditi Shiv Shankar Jaiswal from Delhi Public School Jeddah, Jeddah
Class : Class 4

Ans 2:

yajur from dps vk, delhi
Class : Class 3
True,should’be been C as 22 has two 2’s in itself

Ans 3:

Vidit Jain from Bombay Scottish, Mumbai
Class : Class 6
GOOD

Ans 4:

ANWESHA SUNDARAY from KV, PURI, PURI
Class : Class 4
Yes Answer is fifteen (15) option C See 2,12,20.21.2,2.23.24.25,26,27,28,29,32,42

Ans 5:

Admin from SOF, Noida
Class : Class 10
Answer: C 2,12,20,21,22,23,24,25,26,27,28,29,32,42 14 numbers but total number of 2's are 15 as 22 contains 2 2's

Ans 6:

Admin from SOF, Noida
Class : Class 10
Answer : C

Solution
2,12,20,21,22,23,24,25,26,27,28,29,32,42
22 has 2 '2s' in it. Hence the answer is 15

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Anand Mahajan from ,
Subject :IMO    Class : Class 4

Ans 1:

Admin from SOF, Noida
Class : Class 10
Answer : b
Solution
Smallest : 4608
Largest : 4688
Numbers between smallest and largest : 4640, 4680
Sum = 4640+4680 = 9320
So B is the right answer

Ans 2:

Sunita from Dps, Greater Noida
Class : Class 9
Answer : b Solution Smallest : 4608 Largest : 4688 Numbers between smallest and largest : 4640, 4680 Sum = 4640 4680 = 9320 So B is the right answer

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Yash Mehta from GIIS, Singapore
Subject :IMO    Class : Class 4

Ans 1:

FIONA GOMES from LOTUS VALLEY GURGAON, Gurgaon
Class : Class 4
answer supposes to be C, why mentioned as A????

Ans 2:

NIRMAY JOSEPH from St Columba's School, New Delhi , New Delhi
Class : Class 9
I also fèel so.

Ans 3:

Priya Ponmurugan from Gateway international school, chennai
Class : Class 4
The answer c only...

Ans 4:

Sarthak from St Anthony Senior Secondary School Hiran Magri Udaipur, Udaipur
Class : Class 8
I am agree with Angel Gomes..

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Shramana Bhattacharya from BpDAV School, Hyderabad, Hyderabad
Subject :IMO    Class : Class 8

Ans 1: (Master Answer)

Admin from revisewise, Noida
Class : Class 1
can i buy cialis over the counter http://canadian-pharmasy.com

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Nishtha Pahuja from DPS, Sector45, Gurgaon
Subject :IMO    Class : Class 7

Ans 1:

Hitesh Vora from Bunt Sangha's S M Shetty International School , Mumbai
Class : Class 5
how is answer arrived?

Ans 2:

from , Kolkata
Class : Class 9

Ans 3:

Nisha Nair from City , Pune
Class : Class 7

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Darshan Garg from Sri Chaitanya Techno School, Bengaluru
Subject :IMO    Class : Class 4

Ans 1:

Admin from SOF, Noida
Class : Class 10
Answer : A. 5265
There was a mistake in the options. It has been corrected now.

Solution
Biggest 4 digit number formed from these digits = 8743
Smallest 4 digit number formed from these digits = 3478
Difference = 8743 - 3478 = 5265

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RAJESH DEWANGAN from ,
Subject :IMO    Class : Class 4

Ans 1:

sai ramakrishna GUDIMETLA  from AMM MATRICULATION HIGHER SECONDARY SCHOOL, Chennai
Class : Class 5
Option A 84 m is the right answer. Solution : The area of square is 144 m as given. Hence, the side of square is 12 m. The length of one smaller square in the shaded square is 6 m. Hence the length of the rectangle is 6+6+6+6 =24 the breadth of rectangle is 6+6+6=18 The perimetre of rectangle is 2(l+b) = 2 (24+18) = 2*42 = 84 m

Ans 2:

Vrushti from swami vivekanand english primary school, Mumbai
Class : Class 4
Ans is 84. Area of the square = 12 x 12 = 144 which means 12 is the length of two sides of the square, therefore each side will be 6 and there are 14 sides. Hence the perimeter is 14 x 6 = 84

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Shradha82 from Euro school , Pune
Subject :IMO    Class : Class 4

Ans 1:

Anjala Ambade from ,
Class : Class 4
ans-d

Ans 2:

Reshmi Arora from Lotus valley noida, Noida
Class : Class 4
ooliooli

Ans 3:

Soham Gupta from JSSIS Dubai, Dubai
Class : Class 6

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Agrim Goyal from ,
Subject :IMO    Class : Class 6

Ans 1:

Devang Shukla from Ryan Christian School, Mumbai
Class : Class 9
The answer is C

Ans 2:

Admin from SOF, Noida
Class : Class 10
Answer : C We have corrected the answer. Thanks for pointing out the mistake.

Ans 3:

Rishit Sharma from Nehru World School, Ghaziabad
Class : Class 7
Their answer is wrong

Ans 4:

Khush Narwal from ,
Class : Class 6
C

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