International Maths Olympiad Forum By SOF Olympiad Trainer - Page 499
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Shreyas Singh from Podar International School, Pune
Subject :IMO    Class : Class 5

Ans 1:

Aneek Dey from Little Angel School, karimganj
Class : Class 6
Not all athletes and students are boys, some are girls. Not all students are athletes, either. Vice versa. So, option D is the only Venn diagram that correctly and accurately explicates this. Observation skills and general knowledge are primarily tested in this type of question.

Ans 2:

Sahasra Shanker from KV IIT, Chennai
Class : Class 6
Correct answer is D as per Sof-Olympiad.SolutionSome boys are studentsSome boys are athletesSome students are boysSome students are athletesSome athletes are boysSome athletes are students

Ans 3:

swastik Biswal from St Joseph Convent Higher Secendary school, Sambalpur
Class : Class 5

Ans 4:

Aneek Dey from Little Angel School, karimganj
Class : Class 6

Ans 5:

JOIS GEORGE from Dimension, Singapore
Class : Class 5
isn't it C, because boys are a group, in it there are other groups like students and athletes?

Ans 6:

AREEN from BOLTON, HYDERABAD
Class : Class 6
Ans is A.

Ans 7:

Aaditva from Vasant Valley School, New Delhi
Class : Class 7
Answer is A

Ans 8:

Fareeha siddiqua from Janki Devi public school , Mumbai
Class : Class 5
ans is d and the solution is so pakaaw and unreliable to understand however i got it right

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NYRAH GUPTA from Sat Paul Mittal School, Ludhiana
Subject :IMO    Class : Class 5

Ans 1:

Shreyas Krishna Jayaraman from Bala Vidya Mandir, Adyar, Chennai
Class : Class 9
ans is d because french and german are european languages

Ans 2:

Aarav Hitesh Parikh from Gopal Sharma International School, Mumbai
Class : Class 8
ans is d

Ans 3:

AREEN from BOLTON, HYDERABAD
Class : Class 6
Ans is D.

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ishi gupta from DPS NOIDA, NOIDA
Subject :IMO    Class : Class 4

Ans 1:

rudra from THE KERAL ENGLISH PEOPLE EDUCATION S, BHAVANGER
Class : Class 5
My Answer is D

Ans 2:

Swati Pal from DPS, Bangalore
Class : Class 4

Ans 3:

Aarav Gupta from Delhi Public School Bangalore East, Bangalore
Class : Class 4
ANS IS D

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Vedantanarayanan K A from Shri Vageesha Vidyashram, TIRUCHIRAPALLY
Subject :IMO    Class : Class 6

Ans 1:

Vedantanarayanan K A from Shri Vageesha Vidyashram, TIRUCHIRAPALLY
Class : Class 6
abc

Ans 2:

Saanvi from rvk, bengaluru
Class : Class 9
it is just like-5*5=256*6=36thus,7*7=49

Ans 3:

Vedantanarayanan K A from Shri Vageesha Vidyashram, TIRUCHIRAPALLY
Class : Class 6

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Harshita from Nes, Mulund
Subject :IMO    Class : Class 5

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Harshita from Nes, Mulund
Subject :IMO    Class : Class 5

Ans 1:

AREEN from BOLTON, HYDERABAD
Class : Class 6
Ans is C.

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Harini from vibgyor high, bangalore
Subject :IMO    Class : Class 4

Ans 1:

MANDAR PALKAR from KV DRDO, Bengaluru
Class : Class 2
Place value of 8 in 76,863 is 800.

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Harini from vibgyor high, bangalore
Subject :IMO    Class : Class 4

Ans 1:

Ankit Kumar Mistry from Kalyani Public School, Kolkata
Class : Class 7
The place of 8 and 4 in the number 78045 is 8000 and 40 respectively. 8000-40=7960So the answer is B

Ans 2:

Harini from vibgyor high, bangalore
Class : Class 3

Ans 3:

KARTIK SHINDE from Delhi Public school Rau Indore , indore
Class : Class 4

Ans 4:

Prahit tiwari from Chrysalis high varthur bangalore, Bangalore
Class : Class 4

Ans 5:

Harini from vibgyor high, bangalore
Class : Class 3

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Gayatri Iyer from Sanskriti School, Pune
Subject :IMO    Class : Class 3

Ans 1:

Sarthak Shome from Harvest International, Bangalore
Class : Class 7
q must be 7 and p is 5

Ans 2:

Bhogavalli from Timpany , Visakhapatnam
Class : Class 4

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Sarakshi Pani from JHTS, JAMSHEDPUR
Subject :IMO    Class : Class 1

Ans 1:

Sarakshi Pani from JHTS, JAMSHEDPUR
Class : Class 5
hi

Ans 2:

Harsh Kumar from Maharishi Vidya Mandir, Guwahati
Class : Class 8
Smallest odd number = 1 4 more than the smallest odd number is 5 ∴ First digit is 5 Factors of 2 are 1, 2 Factors of 11 are 1, 11 Common factor of 2 and 11 is 1 ∴ Second digit is 1 Product of first two digits = 1 × 5 = 5 ∴ Third digit is 5 Single digit multiple of 6 is 6 itself. ∴ Fifth digit is 6 Now, sum of fourth digit and fifth digit is 9. ∴ Fourth digit = 9 - 6 = 3 ∴ Required number = 51536

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