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ABCD is parallelogram, G is the point on AB such that AG = 2GB, E is point on DC such that CE = 2DE and F is the point on BC such that BF = 2FC. Then, match the following:
Column-I | Column-II |
P. ar (ADEG) | (i) ar (ABCD) |
Q. ar (∆EGB) | (ii) ar (∆EDG) |
R. ar (∆EFC) | (iii) ar (GBCE) |
S. ar (∆EGB) | (iv) ar (∆EBF) |
P | Q | R | S | |
A | (i) | (ii) | (iii) | (iv) |
B | (iii) | (i) | (iv) | (ii) |
C | (iii) | (ii) | (iv) | (i) |
D | (ii) | (i) | (iii) | (iv) |
Why cant it be C