Subject :NSO Class : Class 10
Subject :NSO Class : Class 4
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Subject :NSO Class : Class 7
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Subject :NSO Class : Class 3
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Subject :NSO Class : Class 6
Ans 3:
Class : Class 9
Please provide solutionHow can it be d???????????????????????????????????????????????????????????????????????
Ans 22:
Class : Class 10
how is the answer D. If u do not send a proper solution then did means u do not know this yourself and u just put this question because u just wanted and just wanted to leave us blank and im pretty sure u guys just chose a random answer
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Subject :NSO Class : Class 3
Ans 4:
Class : Class 9
Answer will be D only. Plastic may or may not be flexible. It depends upon type of plastic.
Ans 17:
Class : Class 7
IT IS C.......................................................................................................................................................
Ans 20:
Class : Class 3
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Ans 21:
Class : Class 4
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Subject :NSO Class : Class 4
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Subject :NSO Class : Class 4
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Subject :NSO Class : Class 9
Ans 1:
Class : Class 9
the wave length in air by v=n.lemda, so 350 = 700 . wavelength so wave length = 0.5 m
Now when it enters in brass, v = 3500 m/s, so new wavelength = 3500 / 700 = 5 m.
So answer is option A, i.e. wavelength will be increased by a factor of 10.
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Subject :NSO Class : Class 9
Ans 1:
Class : Class 9
lets go column wise(up to down)
in the first one, the topmost value is 7. if we multiply this value with the second last value(i.e. 3), we get 21.
now we must add this 21 with the second term(i.e. 8), and we get the last term that is 29.
follow the same logic